Solving Math Word Problems: A Step-by-Step Guide

When tackling math word problems, it’s essential to break down the problem into manageable parts and solve it systematically. Here’s a structured approach to help you solve these problems effectively:

Two Key Steps

  1. Translate the Problem into a Numeric Equation:
    • Convert the words into mathematical expressions.
    • Combine these expressions into a single equation.
  2. Solve the Equation:
    • Follow mathematical rules to find the solution.

Tips for Success

  1. Read the Problem Thoroughly:
    • Start by reading the entire problem to understand the situation.
  2. Identify Information and Variables:
    • List all the known quantities and the variables (unknowns) you need to solve for.
  3. Assign Units to Variables:
    • Attach units of measurement to your variables (e.g., miles, gallons, inches). This helps keep track of what each variable represents.
  4. Define the Desired Answer:
    • Clearly state what you’re trying to find, including its units.
  5. Work Organically and Methodically:
    • Write out your steps clearly. This helps you stay organized and reduces errors.
    • Explain each step as you go, which can clarify your thinking and make it easier to track your progress.
  6. Draw and Label Diagrams if Needed:
    • Visual aids like graphs or pictures can be very helpful. Label them clearly.
  7. Recognize “Key” Words:
    • Certain words in the problem indicate specific mathematical operations. Recognizing these can guide you in forming the correct equation.

Key Words and Operations

Different words in a problem suggest different mathematical operations. Here’s a guide:

Addition (+)

  • Key Words: increased by, more than, combined together, total of, sum, added to
  • Examples:
    • What is the sum of 8 and y? → 8+y8 + y8+y
    • Express the number of apples (x) increased by two. → x+2x + 2x+2
    • What is the total weight of Alphie the dog (x) and Cyrus the cat (y)? → x+yx + yx+y

Subtraction (−)

  • Key Words: less than, fewer than, reduced by, decreased by, difference of
  • Examples:
    • What is four less than y? → y−4y – 4y−4
    • What is nine less than a number (y)? → y−9y – 9y−9
    • What if the number of pizzas (x) was reduced by 6? → x−6x – 6x−6
    • What is the difference between my weight (x) and your weight (y)? → x−yx – yx−y

*Multiplication (× or )

  • Key Words: of, times, multiplied by
  • Examples:
    • What is y multiplied by 13? → 13y13y13y or 13×y13 \times y13×y
    • Three runners averaged “y” minutes. What was their total running time? → 3y3y3y
    • I drive my car at 55 miles per hour. How far will I go in “x” hours? → 55x55x55x

Division (÷ or /)

  • Key Words: per, a, out of, ratio of, quotient of, percent (divide by 100)
  • Examples:
    • What is the quotient of y and 3? → y/3y/3y/3 or y÷3y ÷ 3y÷3
    • Three students rent an apartment for $x per month. What will each pay? → x/3x/3x/3 or x÷3x ÷ 3x÷3
    • “y” items cost a total of $25.00. What is their average cost? → 25/y25/y25/y or 25÷y25 ÷ y25÷y

Common Phrases and Their Translations

  1. “Per” or “a” often means “divided by.”
    1. Example: “30 miles per gallon” → 30 miles/gallon\text{30 miles}/\text{gallon}30 miles/gallon
  2. “Less than” can be tricky.
    1. For example, “1.5 less than x” is x−1.5x – 1.5x−1.5, not 1.5−x1.5 – x1.5−x.
  3. “Quotient/Ratio of” means division.
    • Example: “The ratio of x and y” is x/yx/yx/y.
  4. “Difference of” means subtraction.
    • Example: “The difference of x and y” is x−yx – yx−y.

Practice Examples

  • What if the number (x) of children was reduced by six, and then they had to share twenty dollars? How much would each get?
    • Solution: 20x−6\frac{20}{x – 6}x−620​
  • What is 9 more than y?
    • Solution: y+9y + 9y+9
  • What is the ratio of 9 more than y to y?
    • Solution: y+9y\frac{y + 9}{y}yy+9​
  • What is nine less than the total of a number (y) and two?
    • Solution: (y+2)−9(y + 2) – 9(y+2)−9 or y−7y – 7y−7
  • The length of a football field is 30 yards more than its width (y). Express the length of the field in terms of its width y.
    • Solution: y+30y + 30y+30

By following these steps and recognizing key words, you’ll be better equipped to translate word problems into equations and solve them accurately.